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ISQI ISTQB Certified Tester Foundation Level (CTFL) v4.0 Sample Questions (Q186-Q191):

NEW QUESTION # 186
A typical objective of testing is to ensure that:

  • A. testing is used to drive the development of a software
  • B. there are no defects in a software that is about to be released
  • C. a software has been properly covered
  • D. a software has been tested using a combination of test techniques

Answer: D

Explanation:
Explanation
This answer is correct because a typical objective of testing is to ensure that a software has been tested using a combination of test techniques, such as black-box, white-box, or experience-based techniques, that are appropriate for the test objectives, test levels, and test types. Testing using a combination of test techniques can increase the effectiveness and efficiency of testing, as different techniques can target different aspects of the software quality, such as functionality, usability, performance, security, reliability, etc. Testing using a combination of test techniques can also reduce the risk of missing defects that could be detected by one technique but not by another. References: ISTQB Foundation Level Syllabus v4.0, Section 2.3.1.1, Section
2.3.2


NEW QUESTION # 187
Following a risk-based testing approach you have designed 10 tests to cover a product risk with a high-risk level. You want to estimate, adopting the three-point test estimation technique, the test effort required to reduce the risk level to zero by executing those 10 tests. You made the following three initial estimates:
* most optimistic = 6 person hours
* most likely = 30 person hours
* most pessimistic = 54 person hours
Based only on the given information, which of the following answers about the three-point test estimation technique applied to this problem is true?

  • A. The final estimate is between 6 person hours and 54 person hours
  • B. The final estimate is between 22 person hours and 38 person hours
  • C. The final estimate is exactly 30 person hours because the technique uses the initial most likely estimate as the final estimate
  • D. The final estimate is exactly 30 person hours because the technique uses the arithmetic mean of the three initial estimates as the final estimate

Answer: B

Explanation:
The three-point test estimation technique is a method of estimating the test effort based on three initial estimates: the most optimistic, the most likely, and the most pessimistic. The technique uses a weighted average of these three estimates to calculate the final estimate, which is also known as the expected value. The formula for the expected value is:
Expected value = (most optimistic + 4 * most likely + most pessimistic) / 6 Using the given values, the expected value is:
Expected value = (6 + 4 * 30 + 54) / 6 Expected value = 30 person hours However, the expected value is not the only factor to consider when estimating the test effort. The technique also calculates the standard deviation, which is a measure of the variability or uncertainty of the estimates. The formula for the standard deviation is:
Standard deviation = (most pessimistic - most optimistic) / 6
Using the given values, the standard deviation is:
Standard deviation = (54 - 6) / 6 Standard deviation = 8 person hours
The standard deviation can be used to determine a range of possible values for the test effort, based on a certain level of confidence. For example, using a 68% confidence level, the range is:
Expected value ± standard deviation
Using the calculated values, the range is:
30 ± 8 person hours
Therefore, the final estimate is between 22 person hours and 38 person hours, which is option A.
References: ISTQB Certified Tester Foundation Level Syllabus v4.01, Section 2.3.2, page 24-25; ISTQB Glossary v4.02, page 33.


NEW QUESTION # 188
Which of the following statements about the shift-left approach is true?

  • A. Shift-left in testing can be implemented only in Agile/DevOps frameworks, as it relies completely on automated testing activities performed within a continuous integration process
  • B. Performance testing performed during component testing, is a form of shift-left in testing that avoids planning and executing costly end-to-end testing at the system test level in a production-like environment
  • C. Continuous integration supports shift-left in testing as it can reduce the time between the introduction of a defect and its detection, thereby reducing the cost to fix it
  • D. Shift-left in testing can be implemented in several ways to find functional defects early in the lifecycle, but it cannot be relied upon to find defects associated with non-functional characteristics

Answer: C

Explanation:
This answer is correct because shift-left in testing is an approach that aims to perform testing activities as early as possible in the software development lifecycle, in order to find and fix defects faster and cheaper, and to improve the quality of the software product. Continuous integration is a practice that supports shift-left in testing, as it involves integrating and testing the software components frequently, usually several times a day, using automated tools and processes. Continuous integration can reduce the time between the introduction of a defect and its detection, thereby reducing the cost to fix it and the risk of accumulating defects that could affect the functionality or performance of the software product. References: ISTQB Foundation Level Syllabus v4.0, Section 3.1.1.3, Section 3.2.1.3


NEW QUESTION # 189
Which ONE of the following options MOST ACCURATELY describesstatement testing?

  • A. In statement testing, the coverage items are branches, and the aim is to design test cases to exercise branches in the code until an acceptable level of coverage is achieved, expressed as a percentage.
  • B. In statement testing, the coverage items are decisions and statements. The aim is to design test cases that exercise statements in the code until an acceptable level of coverage is achieved, expressed as a percentage.
  • C. In statement testing, the coverage items are control flow transfers between branches. The aim is to design test cases to exercise branches in the code until an acceptable level of coverage is achieved, expressed as a percentage.
  • D. In statement testing, the coverage items are executable statements. The aim is to design test cases that exercise statements in the code until an acceptable level of coverage is achieved, expressed as a percentage.

Answer: D

Explanation:
Statement testingaims to executeevery executable statementin the source code at least once.
* (D) is correctas statement testing ensuresmaximum statement execution.
* (A) describes branch testing, which focuses on flow transfers.
* (B) and (C) incorrectly mix decision testing and branch testing concepts.


NEW QUESTION # 190
A requirement specifies that a certain identifier (ID) must be between 5 and 10 characters long, must contain only alphanumeric characters, and its first character must be a letter. As a tester, you want to apply one-dimensional equivalence partitioning to test this ID. This means that you have to apply equivalence partitioning individually: to the length of the ID, the type of characters contained within the ID, and the type of the first character of the ID.
What is the number of partitions to cover?

  • A. 0
  • B. 1
  • C. 2
  • D. 3

Answer: A

Explanation:
To determine the number of partitions using one-dimensional equivalence partitioning, we need to consider each aspect of the ID requirement individually.
* Length of the ID:
* Valid partitions: 5 to 10 characters (1 partition)
* Invalid partitions: Less than 5 characters, more than 10 characters (2 partitions)
* Type of characters:
* Valid partitions: Alphanumeric characters (1 partition)
* Invalid partitions: Non-alphanumeric characters (1 partition)
* Type of first character:
* Valid partitions: First character is a letter (1 partition)
* Invalid partitions: First character is not a letter (1 partition)
Adding these together, we have a total of 1 (valid length) + 2 (invalid lengths) + 1 (valid type) + 1 (invalid type) + 1 (valid first character) + 1 (invalid first character) = 7 partitions.


NEW QUESTION # 191
......

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